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2.1x^2+3x-270=0
a = 2.1; b = 3; c = -270;
Δ = b2-4ac
Δ = 32-4·2.1·(-270)
Δ = 2277
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2277}=\sqrt{9*253}=\sqrt{9}*\sqrt{253}=3\sqrt{253}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{253}}{2*2.1}=\frac{-3-3\sqrt{253}}{4.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{253}}{2*2.1}=\frac{-3+3\sqrt{253}}{4.2} $
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